1. How manynumbers Can you make using the digits2, 3, 4, 5, 9 (a witho

1.	1. How manynumbers Can you make using the digits2, 3, 4, 5, 9 (a without repeatation if digits)(b with respitation of digits)
Answer» $\displaystyle \huge\red{\underline{\underline{Solution}}}$ The number consists of 4 digits. So the positions are UNIT PLACE Ten place Hundred place Thousand Place The digits are 2, 3, 4, 5, 9 $\blacksquare \:$ REPEATATION ARE ALLOWED Unit Place can filled in 5 ways Ten place can filled in 5 ways Hundred place can filled in 5 ways Thousand Place can filled in 5 ways So the total numbers can be FORMED $= 5 \times 5 \times 5 \times 5 = 625$ $\blacksquare$ *REPEATATION ARE* *NOT* *ALLOWED* Unit Place can filled in 5 ways Ten place can filled in 4 ways Hundred place can filled in 3 ways Thousand Place can filled in 2 ways So the total numbers can be formed $\: = 5 \times 4 \times 3 \times 2 = 120$

1. How manynumbers Can you make using the digits2, 3, 4, 5, 9 (a without repeatation if digits)(b with respitation of digits)

Answer»

$\displaystyle \huge\red{\underline{\underline{Solution}}}$

The number consists of 4 digits.

So the positions are

The digits are 2, 3, 4, 5, 9

$\blacksquare \:$ REPEATATION ARE ALLOWED

So the total numbers can be FORMED

$= 5 \times 5 \times 5 \times 5 = 625$

$\blacksquare$ REPEATATION ARE NOT ALLOWED

So the total numbers can be formed

$\: = 5 \times 4 \times 3 \times 2 = 120$