1)if y=sin^2x,then dy/dx value at x=45° is 2)if y=e^5x,then dy/dx value at x=03)if f(2)=4 andf'(2)=1 then lim xf(2)-2f(x)/x-2 xto24)if y=1-tan^2theeta/1+tan^2theeta then the value of dy/dtheeta at theeta=-pie^c/4 is k, then 7k/85)if x=asint, y=a cos t then the value of dy/dx at t=150° is k,the root3k/4 is6)if y=2^ax and dy/dx=log256 at x=1,then 5a/4 is pls answerr theese correctly if anything irrelavent is posted i will report the answer pls answer before 20minutes

1)if y=sin^2x,then dy/dx value at x=45° is 2)if y=e^5x,then dy/dx v

1.	1)if y=sin^2x,then dy/dx value at x=45° is 2)if y=e^5x,then dy/dx value at x=03)if f(2)=4 andf'(2)=1 then lim xf(2)-2f(x)/x-2 xto24)if y=1-tan^2theeta/1+tan^2theeta then the value of dy/dtheeta at theeta=-pie^c/4 is k, then 7k/85)if x=asint, y=a cos t then the value of dy/dx at t=150° is k,the root3k/4 is6)if y=2^ax and dy/dx=log256 at x=1,then 5a/4 is pls answerr theese correctly if anything irrelavent is posted i will report the answer pls answer before 20minutes
Answer» mark me as BRAINLIEST please please mark me as brainliest pleaseAnswer1Given xe xy =y+sin 2 X ...(1)on putting x=0, we get 0.e 0 =y+0⇒y=0on differentiating (1) both sides w.r.t x, we get1.e xy +x.e xy (x. dxdy +y)= dxdy +2sinxcosxOn putting x=0,y=0, we gete 0 +0(0+0)=[ dxdy ]+2sin0⇒ dxdy =1