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1)In the figure XY is parallel to QR. PX=2cm,QX=4cm PR=9cm? a)Find PY=YR? b)Find the length of PY.Q? |
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Answer» - In ∆ PQR, XY || QR. PX = 2 cm. QX = 4 cm. PR = 9 cm. To Find :- PY = ? YR = ? Solution :- we know that, Basic proportionality theorem :- If a line is drawn parallel to one side of a triangle to INTERSECT the other two sides in distinct points then the other two sides are divided in the same ratio . since XY || PR . so, PX / XQ = PY / YR . putting values we get, → (2/4) = PY/YR → 1/2 = PY/YR → PY : YR = 1 : 2 now, dividing PR(9 cm) in 1 : 2 , we get, → PY = (1/3) * 9 → PY = 3 cm. (ANS.) and,→ YR = (2/3) * 9 → YR = 6 cm. (Ans.) LEARN more :- In ABC, AD is angle bisector,angle BAC = 111 and AB+BD=AC find the value of angle ACB=? brainly.in/question/16655884 |
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