1 kg of an aquous solution of Sucrsop is colled and maintainedat -4^(@)C. How much ice will be separanted out if the molality of the solution is 0.75 ? K_(t)(H_(2)O)=1.876 kg "mol"^(-1)K.

1 kg of an aquous solution of Sucrsop is colled and maintainedat -4^(@

1.	1 kg of an aquous solution of Sucrsop is colled and maintainedat -4^(@)C. How much ice will be separanted out if the molality of the solution is 0.75 ? K_(t)(H_(2)O)=1.876 kg "mol"^(-1)K.
Answer» SOLUTION :Source is a non-electrolyte Molecular weight of sucrose `C_(12)H_(2)O_(11)=M=342 gm "mol"^(-1)` Molality of the solution `0.75m` `=0.75"mol" KG^(-1)` SOLVENT `=256.5` gm Sourcose per kg solvent Hence weight of 1 molal solution `(256.5)/(1256.5)xx1000=204.14 gm` Weight of solvent `(H_(2)O)` present in 1kg solution `=1000-204.14 gm` SINCE depressionnin freezing point. `DeltaT_(t)=K_(t)xx(W)/(m)xx(1000)/(W)` where W= weight of solvent W= weight of the solute or `4=1.86xx(256.5)/(342)xx(1000)(W)` `:.W=348.75gm` i.e., weight of solvent required to maintain this solutionat `-4^(@)C` `W=348.75 gm` Hence rest weight of `H_(2)O` will convert into ice Hence amount of ince formed `=795.86-348.477.11 gm`