1.

1 L of a gas at S.T.P.weighs 1.97 g. What is the vapour density of the gas?

Answer»

Solution :22.4 L of the gas at S.T.P. will weigh `=1.97xx22.4=44.1g`, i.e., MOLECULAR mass = 44.1. Hence, vapour DENSITY `=44.1//2=22.05`.


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