-step explanation:9th8th7th6thSelina ICSE SolutionsML Aggarwal SolutionsICSE PapersISC PapersSkip to contentLearn CramQuestion and Answer forum for K12 Students MenuMaharashtra Board Class 8 Maths Solutions Chapter 5 Expansion Formulae Practice Set 5.1August 13, 2019 by LaxmiMaharashtra State Board Class 8 Maths Solutions Chapter 5 Expansion Formulae Practice Set 5.1Question 1.Expand :i. (a + 2)(a – 1)ii. (m – 4)(m + 6)iii. (p + 8) (p – 3)iv. (13 + X)(13 – x)v. (3x + 4y) (3x + 5y)vi. (9x – 5t) (9x + 3t)vii. (m+23)(m−73)viii. (x+1x)(x−1x)IX. (1y+4)(1y−9)SOLUTION:i. (a + 2)(a – 1)= a² + (2 – 1) a + 2 × (-1)..[∵ (x + A) (x + B) = x² + (A + B)x + AB]= a² + a – 2ii. (m – 4)(m + 6)= m² + (- 4 + 6) m + (-4) × 6…[∵ (x + a) (x + b) = x² + (a + b)x + ab]= m² + 2m – 24 iii. (p + 8) (p – 3)= p² + (8 – 3) p + 8 x (-3)…[∵ (x + a) (x + b) = x² + (a + b)x + ab]= p² + 5p – 24 iv. (13 + x) (13 – x)= (13)² + (x – x) 13 + x × (-x)…[∵ (x + a) (x + b) = x² + (a + b)x + ab]= 169 + 0 × 13 – x²= 169 – x²v. (3x + 4y) (3x + 5y)= (3x)² + (4y + 5y) 3x + 4y × 5y…[∵ (x + a) (x + b) = x² + (a + b)x + ab]= 9x² + 9y × 3x + 20y²= 9x² + 27xy + 20y²vi. (9x – 5t) (9x + 3t)= (9x)² + [(-5t) + 3t] 9x + (-5t) × 3t…[∵ (x + a) (x + b) = x² + (a + b)x + ab]= 81x² + (-2t) × 9x – 15t²= 81x² – 18xt – 15t²vii. (m+23)(m−73)Maharashtra Board Class 8 Maths Solutions Chapter 5 Expansion Formulae Practice Set 5.1 1viii. (x+1x)(x−1x)Maharashtra Board Class 8 Maths Solutions Chapter 5 Expansion Formulae Practice Set 5.1 2