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1 M NaOH solution was slowly added in to 1000 mL of 183.75 g impure H_(2)SO_(4) solution and the following plot was obtained. The percentage purity of H_(2)SO_(4) sample and slope of the curve respectively are: |
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Answer» `75%` Moles of NaOH consumed when reacted with `H^(+) = 3xx1` (because `3L` of NaOH is added with `1M` cons.) moles of `H_(2)SO_(4)` PRESENT in sample `= 1.5` (because every `H_(2)SO_(4)` has `2H^(+)`) weight of `H_(2)SO_(4)` in sample `= 1.5xx98 = 147g` `%` PURITY `= (147)/(183.75)xx100=80%` |
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