1. Mahima Covers one seventh of her journey on Monday. She Covers thre

1.	1. Mahima Covers one seventh of her journey on Monday. She Covers three fourth of her Journey Tuesday , (how many portion she has covered so far)
Answer» Given, Mahima covers in Monday = ⅐ of her journey Mahima covers in Tuesday = ¾ of her journey To find, The amount of portion of her journey that she has COVERED so far. Solution, We can simply solve this MATHEMATICAL problem by using the following mathematical process. Here, we just need to add the two portions of journey covering, of Monday and Tuesday. Total covered journey = ⅐ + ¾ = (4+21)/28 = 25/28 (This portion of journey she has covered in the last two DAYS.) HENCE, she has covered 25/28 of her journey so far.

1. Mahima Covers one seventh of her journey on Monday. She Covers three fourth of her Journey Tuesday , (how many portion she has covered so far)

Answer»

Given,

Mahima covers in Monday = ⅐ of her journey

Mahima covers in Tuesday = ¾ of her journey

To find,

The amount of portion of her journey that she has COVERED so far.

Solution,

We can simply solve this MATHEMATICAL problem by using the following mathematical process.

Here, we just need to add the two portions of journey covering, of Monday and Tuesday.

Total covered journey

= ⅐ + ¾

= (4+21)/28

= 25/28

(This portion of journey she has covered in the last two DAYS.)

HENCE, she has covered 25/28 of her journey so far.

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