1.

1 mol of [Agl]I^(-) can be coagulated by:

Answer»

1 mol of `PB(NO_3)_2`
`1/2 mol of Pb(NO_3)_2`
`2/3 mol of Pb(NO_3)_2`
None of these

Solution :`Pb(NO_3)_2+2[Ag]I^(-) to PbI_2 downarrow +AGL downarrow`
`2[Ag]I^(-) =- Pb(NO_3)_2`
`THEREFORE [Ag]I^(-)=-1/2 Pb(NO_3)_2`


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