1 mole of an ideal gas is maintained at 4.1 atm and at a certain tempe

1.	1 mole of an ideal gas is maintained at 4.1 atm and at a certain temperature absorbs 3710 J heat and expands to 2 litres. Calculate the entropy change in expansion process.
Answer» Pressure of an ideal gas P_i = 4.1 atm. Expansion in volume = ∆V = 2 litres Heat absorbed = q = 3710 J Entropy change = ∆S = ? For an ideal gas PV = RT for one mole. T = PV/R = 4.1x₂/0.830 = 100°C T = 100 + 273 = 373 K. ∆S = q/T_(K)= 3710/373 Entropy change = 9.946 JK^-1

1 mole of an ideal gas is maintained at 4.1 atm and at a certain temperature absorbs 3710 J heat and expands to 2 litres. Calculate the entropy change in expansion process.

Answer»

Pressure of an ideal gas P_i = 4.1 atm.

Expansion in volume = ∆V = 2 litres

Heat absorbed = q = 3710 J

Entropy change = ∆S = ?

For an ideal gas PV = RT for one mole.

T = PV/R = 4.1x₂/0.830 = 100°C

T = 100 + 273 = 373 K.

∆S = q/T_(K)= 3710/373

Entropy change = 9.946 JK^-1

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1 mole of an ideal gas is maintained at 4.1 atm and at a certain temperature absorbs 3710 J heat and expands to 2 litres. Calculate the entropy change in expansion process.

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