1 mole of gas expands isothermally at `37^(@)C`. The amount of heat is absorbed by it until its volume doubled is `(R= 8.31 J mol^(-1) K^(-1))`A. 411.25 calB. 418.50 calC. 420.25 calD. 425.40 cal

1 mole of gas expands isothermally at `37^(@)C`. The amount of heat is

1.	1 mole of gas expands isothermally at `37^(@)C`. The amount of heat is absorbed by it until its volume doubled is `(R= 8.31 J mol^(-1) K^(-1))`A. 411.25 calB. 418.50 calC. 420.25 calD. 425.40 cal
Answer» Correct Answer - D Here `T=37^(@)c=37+273=310 K V_(2)=2V` work done in siothermal process is `W=nRTln(V_(2))/(V_(1))=1xx8.31xx310xxln(2V_(1))/(V_(1))` `=8.31xx310xxln2=1.786xx10^(3)` Amount of heat absorbedc =`(1.786xx10^(3))/(4.2)` cal =425.4 cal

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1 mole of gas expands isothermally at `37^(@)C`. The amount of heat is absorbed by it until its volume doubled is `(R= 8.31 J mol^(-1) K^(-1))`A. 411.25 calB. 418.50 calC. 420.25 calD. 425.40 cal

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