1 mole of `H_(2) and 2` moles of `I_(2)` are taken initially in 2 litre vessel. The number of moles of `H_(2)` at equlibrium is `0.2.` Then the number of moles of `I_(2) and HI` at equliberium areA. `1.2,1.6`B. `1.8,2.4`C. `0.4,2.4`D. `0.8,2.0`

1 mole of `H_(2) and 2` moles of `I_(2)` are taken initially in 2 litr

1.	1 mole of `H_(2) and 2` moles of `I_(2)` are taken initially in 2 litre vessel. The number of moles of `H_(2)` at equlibrium is `0.2.` Then the number of moles of `I_(2) and HI` at equliberium areA. `1.2,1.6`B. `1.8,2.4`C. `0.4,2.4`D. `0.8,2.0`
Answer» Correct Answer - A At equlibrium number of moles of `H_(2)=0.2` moles 0.8 moles of `H_(2)` reacts with `(2-0.8)` moles of `I_(2)` to from `(2xx0.8)` moles of HI `H_(2)+I_(2)hArr2HI` `{:("Inital no.",1,2,0),("of mole",,,),("No of moles"0.,2,,(-20.8)2xx0.8),("at equlibrium",,=1.2,=1.6):}`

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1 mole of `H_(2) and 2` moles of `I_(2)` are taken initially in 2 litre vessel. The number of moles of `H_(2)` at equlibrium is `0.2.` Then the number of moles of `I_(2) and HI` at equliberium areA. `1.2,1.6`B. `1.8,2.4`C. `0.4,2.4`D. `0.8,2.0`

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