1.

1 mole of liquid A and 2 moles of liquid B make a solution having a total vapour pressure of 38 torr. The vapour pressures of pure A and pure B are 45torr and 36 torr respectively. The described solution

Answer»

is an ideal solution
shows negative deviation
is a minimum boiling azeotrope
has volume GREATER than the sum of individual volumes

Solution :According to Raoult's law,
`p_(A)=x_(A)xxp_(A)^(@)=(1)/(3)xx"45 torr"="15 torr"`
`p_(B)=x_(B)xxp_(B)^(@)=(2)/(3)xx"36 torr = 24 torr"`
`therefore"PRESSURE expected by Raoult's law "=15+24`
= 39 torr
Thus, observed pressure (38 torr) is less than expected value.
Hence, the solution shows negative deviation.


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