1.

1 mole of N_(2) and 3 moles of H_(2) filled in a one-litre bulb were allowed to react. When the reaction attained equilibrium, two-thirds of N_(2) converted to NH_(3)(N_(2)+3H_(2)hArr2NH_(3)). If a hole is then made in the bulb, the mole ratio of the gases N_(2),H_(2) andNH_(3) effusing out initially would be respectively.

Answer»

`1:3:4`
`sqrt28:SQRT2:SQRT17`
`1/sqrt28:1/sqrt2:1/sqrt17`
`1/sqrt28:3/sqrt2:4/sqrt17`

ANSWER :D


Discussion

No Comment Found