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1 mole of N_(2) and 3 moles of H_(2) filled in a one-litre bulb were allowed to react. When the reaction attained equilibrium, two-thirds of N_(2) converted to NH_(3)(N_(2)+3H_(2)hArr2NH_(3)). If a hole is then made in the bulb, the mole ratio of the gases N_(2),H_(2) andNH_(3) effusing out initially would be respectively. |
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Answer» `1:3:4` |
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