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1 mole of naphthalene `(C_(10)H_(8))` was burnt in oxygen gas at `25^(@)C` at constant volume. The heat evolved was found to be 5138.8kJ. Calculate the heat of reaction at constant pressure. `(R=8.3JK^(-1)" "mol^(-1))` |
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Answer» Correct Answer - 5143.8kJ Water is present in liquid state at `25^(@)C` and naphthalene in solid state. |
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