1.

1 .On factorizing (3a²bc + 9ab²c + 21abc?), we get a) 3abc(3a+3b+7c)b) 3abc(a+b+c)c)abc(a+3b+7c)d)3abc(a+3b+7c)​

Answer»

3abc(a+3b+7c)Step-by-step EXPLANATION:Just take the COMMON out of the three termsThank you. Please mark me as Brainliest.



Discussion

No Comment Found

Related InterviewSolutions