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1 .On factorizing (3a²bc + 9ab²c + 21abc?), we get a) 3abc(3a+3b+7c)b) 3abc(a+b+c)c)abc(a+3b+7c)d)3abc(a+3b+7c) |
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Answer» 3abc(a+3b+7c)Step-by-step EXPLANATION:Just take the COMMON out of the three termsThank you. Please mark me as Brainliest. |
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