InterviewSolution
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`(1+sec22^(@)+cot68^(@))(1-"co s ec"22^(@)+tan68^(@))` व्यंजक का मान बताइए ? |
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Answer» Correct Answer - d `(1+sec22+cot68)` `(1-co s ec22+tan68)` `=(1+sec 22+tan22)` `=1+sec22+tan22-co s ec22-sec22co s ec22-co s ec22tan22+cot22+cot22sec22+tan22cot22)` `=1+sec22+tan22-co s ec22-(1)/(cos22)(1)/(sin22)-(1)/(sin22)(sin22)/(cos22)` `+cot22+(cos22)/(sin22)xx(1)/(cos22)+1` lt brgt `=1+(1)/(cos22)+(sin22)/(cos22)-(1)/(sin22)` `(1)/(cos22)(1)/(sin22)-(1)/(cos22)+cot22(1)/(sin222)+1` `1+(sin22)/(cos22)+(cos22)/(sin22)-(1)/(sin22)` `(1)/(cos22)+1` `2+(cos^(2)22+cos^(2)22)/(cos22sin22)-(1)/(sin22)` `(1)/(cos22)` `rArr2+(1)/(cos22sin22)-(1)/(sin22cos22)` =2 |
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