1.

`(1+sec22^(@)+cot68^(@))(1-"co s ec"22^(@)+tan68^(@))` व्यंजक का मान बताइए ?

Answer» Correct Answer - d
`(1+sec22+cot68)`
`(1-co s ec22+tan68)`
`=(1+sec 22+tan22)`
`=1+sec22+tan22-co s ec22-sec22co s ec22-co s ec22tan22+cot22+cot22sec22+tan22cot22)`
`=1+sec22+tan22-co s ec22-(1)/(cos22)(1)/(sin22)-(1)/(sin22)(sin22)/(cos22)`
`+cot22+(cos22)/(sin22)xx(1)/(cos22)+1` lt brgt `=1+(1)/(cos22)+(sin22)/(cos22)-(1)/(sin22)`
`(1)/(cos22)(1)/(sin22)-(1)/(cos22)+cot22(1)/(sin222)+1`
`1+(sin22)/(cos22)+(cos22)/(sin22)-(1)/(sin22)`
`(1)/(cos22)+1`
`2+(cos^(2)22+cos^(2)22)/(cos22sin22)-(1)/(sin22)`
`(1)/(cos22)`
`rArr2+(1)/(cos22sin22)-(1)/(sin22cos22)`
=2


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