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(1-tanQ×tanQ)+(1+1/(tanQ×tanQ)=1/(secQ×secQ+sinQ×sinQ×sinQ×sinQ) |
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Answer» Answer: Zeroes are 1/2+2√3 and 1/2-2√3 sum of zeroes = 1/2+2√3 + 1/2-2√3 = 1/2 + 1/2 = 1 product of zeroes = 1/2+2√3 x 1/2-2√3 = [ 1/2 ] ² - [ 2√3 ]² = 1/4 - 12 = 1/4 - 48 / 4 = -47 /4 Quadratic equation x² - [ sum of zeroes ]x + product of zeroes =x² - x + -47/4............
tex] \BEGIN{lgathered}\tt \implies \: (25 - x) {}^{2} = (x) {}^{2} + (5) {}^{2} \\ \tt \implies625 - 50 + x {}^{2} = x {}^{2} + 25 \\ \tt \implies - 50x |
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