1. The Fig. 11.6 shows two paths drawn inside a rectangular field 50 m long 001 wide. The width of each path is 5 m. Find the area of the shaded portion.

1. The Fig. 11.6 shows two paths drawn inside a rectangular field 50 m

1.	1. The Fig. 11.6 shows two paths drawn inside a rectangular field 50 m long 001 wide. The width of each path is 5 m. Find the area of the shaded portion.
Answer» -STEP EXPLANATION:Length of rectangle ABCD =50 mBreadth of rectangle ABCD =5 MAREA of rectangle ABCD =L×B =50×5 =250 m 2 Length of rectangle EFGH =35 mBreadth of rectangle EFGH =5 mArea of rectangle EFGH =35×5 =175 m 2 Length of rectangle ILKL =5 mBreadth of rectangle IJKL =5 mArea of rectangle IJKL =35×5 =175 m 2 Now,Area of shaded portion = (Area of ABCD + Area of EFGH) − Area of IJKL =(250+175)−25 =425−25 =400 m 2 Hence area of shaded portion is 400 m 2