InterviewSolution
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InterviewSolution
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`(1 + x + x^(2))^(n) = a_(0) +a_(1)x + a_(2) x^(2) +...+ a_(2n )x^(2n)` , then `a_(0) a_(2n) - a_(1) a_(2r+1) + a_(2) a_(2r+2) - a_(3) a_(2r+3) +...+a_(2n-2r)a_(2n)=` . |
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Answer» Correct Answer - d On equating the coefficients of `x^(2n +1)` on both sides of (v) in illustration 25, we get `a_(0) a_(2n) - a_(1) a_(2r+1) + a_(2) a_(2r+2) - a_(3) a_(2r+3) +...+a_(2n-2r)a_(n+r)`. |
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