1.

1 xx 10^(-3) mole of HCl is added to a buffer solution made up of 0.01 M acetic acid and 0.01 M sodium acetate. The final pH of the buffer will be (given pK_(a) of acetic acid is 4.75 at 25^(@)C)

Answer»

`4.60`
4.66
4.75
4.8

Solution :`{:(CH_(3)COO^(-),+,H^(+),RARR,CH_(3)COOH),(" "0.01,,0.001,,""0.01),(0.01-0.001,,,,0.01+0.001),(= 0.009,,,,= 0.011):}`
`pH = pKa + log.(["SALT"])/(["ACID"]) = 4.75 + log. (0.009)/(0.011) = 4.66`.


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