1.

1 xx10^(-3)mole of HCI is added to a buffer solution made up of 0.01 M acetic acid and 0.01 M sodium acetate. The final pH of the buffer will be given, PK of acetic acid is 4.75 at 25^@ C)

Answer»

`4.60 `
`4.66`
`4.75`
`4.8`

SOLUTION :
`PH =pK_a + LOG(["SALT"])/(["ACID"])=4.75 + log( 0.009 )/( 0.011 ) = 4.66`


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