1.

`(1 + xy) ydx + (1-xy)xdy = 0`A. `(x)/(y)+(1)/(xy)=k`B. `log((x)/(y))=(1)/(xy)+k`C. `(x)/(y)+(1)/(xy)=k`D. `log((x)/(y))= xy + k`

Answer» Correct Answer - C
`y dx + x dy + xy^(2) dx - x^(2) y dy = 0`
`rArr" "(y dx + x dy)/(x^(2)y^(2))+(dx)/(x)-(dy)/(y)=0`
On integrating, we get
`-(1)/(xy)+log x - log y = k rArr "log"(x)/(y)=(1)/(xy)+k`


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