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`(1 + xy) ydx + (1-xy)xdy = 0`A. `(x)/(y)+(1)/(xy)=k`B. `log((x)/(y))=(1)/(xy)+k`C. `(x)/(y)+(1)/(xy)=k`D. `log((x)/(y))= xy + k` |
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Answer» Correct Answer - C `y dx + x dy + xy^(2) dx - x^(2) y dy = 0` `rArr" "(y dx + x dy)/(x^(2)y^(2))+(dx)/(x)-(dy)/(y)=0` On integrating, we get `-(1)/(xy)+log x - log y = k rArr "log"(x)/(y)=(1)/(xy)+k` |
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