1.

10^(-2)F charge can remove entrie Cl_2 from 100 ml of HCl solution. What is the P^(H) of the solution initially

Answer»


Solution :`1F to ` remove1 MOLE ` Cl^(Ɵ)` to ` (1)/(2)Cl_2 , 10^(-2) F to ` remove ` 10^(-2)` mole `Cl^(Ɵ)` to `((10^(-2))/(2))Cl_2`
`(H^(OPLUS)) = [HCl]=(n)/(v) = (10^(-2)" mole")/((100//1000)) = 10^(-2) xx 10 = 10^(-1) , P^(H) =1`


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