10. 45 g of water at 50°C in a beaker is cooled when50 g of copper at

1.	10. 45 g of water at 50°C in a beaker is cooled when50 g of copper at 18°C is added to it. The contentsare stirred till a final constant temperature is reached.Calculate the final temperature. The specific heatcapacity of copper is 0.39 J g K-1 and that of waterİS 4-2 J g-1 K-1. State the assumption used.Ans. 47°CAssumption : There is no loss of heat.lus
Answer» Heat gained by copper = m × C × θ = 50 × 0. 39 × (T − 18) Heat lost by water = 45 × 4. 2 × (50 − T) Heat lost = Heat gained 45 × 4. 2 × (50 − T) = 50 × 0. 39 × (T − 18) 9450 − 189 T = 19. 5 T − 351208. 5 T = 9801 Or T = 47°C (Approx)

10. 45 g of water at 50°C in a beaker is cooled when50 g of copper at 18°C is added to it. The contentsare stirred till a final constant temperature is reached.Calculate the final temperature. The specific heatcapacity of copper is 0.39 J g K-1 and that of waterİS 4-2 J g-1 K-1. State the assumption used.Ans. 47°CAssumption : There is no loss of heat.lus

Answer»

Heat gained by copper = m × C × θ = 50 × 0. 39 × (T − 18)

Heat lost by water = 45 × 4. 2 × (50 − T)

Heat lost = Heat gained

45 × 4. 2 × (50 − T) = 50 × 0. 39 × (T − 18)

9450 − 189 T = 19. 5 T − 351208. 5 T = 9801 Or T = 47°C (Approx)

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