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10^(-6) M NaOH is diluted 100 times. The pH of the diluted base is |
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Answer» Between 5 and 6 When 100 TIMES diluted, `[OH^(-)] = (10^(-6))/(10^(2)) = 10^(-8)` As it is weak base, but proteolysis of water will also TAKE place. So, the contribution of `OH^(-)` ions from water must also be considered. `:.` Total `[OH^(-)] = 10^(-8) + 10^(-7)`. |
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