1.

10^(-6)M NaOH is diluted to 100 times. The pH of the diluted base is

Answer»

between 5 and 6
between 6 and 7
between 10 and 11
between 7 and 8

Solution :`[OH^(-)]` of `10^(-6)` M NaOH `=10^(-6)`
when 100 times DILUTED
`[OH^(-)]=(10^(-6))/(10^(2))=10^(-8)`
As it is a WEAK base, autoprotolysis of water will also take place. So, thecontributaioin of `OH^(-)` ions from water MUST also be considered.
`:.` Total `[OH^(-)]=10^(-8)+[OH^(-)]_("water")`


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