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10^(6) positrons are flowingnormallythrough an area in forward directionand sameamountof electrons are flowing in backward directionin the interval of 10 ms. Findthe current through thearea. |
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Answer» Solution :`q_(+) = 10^(6) xx 1.6 xx 10^(-19) C = 1.6 xx 10^(-13)C` `q_(-) = 10^(16) xx (- 1.6 xx 10^(-19) C)= - 1.6 xx 10^(-13) C` Net chargethrough THEAREA q = ` q_(+)- q_(-) = 1.6 xx 10^(-13) C- (-1.6 xx 10^(-13)C)` ` = 3.2 xx 10^(-13)C` Currentthrough thearea ` L = (q)/(t) = ( 3.2 xx 10^(-13) C)/(10 xx 10^(-13) S) = 3.2 X 10^(-11) A ` |
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