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`10` different books and `2` different pens are given to `3` boys so that each gets equal number of things. The probability that the same boy does not receive both the pens isA. `5//11`B. `7//11`C. `9//11`D. `6//11` |
Answer» Correct Answer - C `(c )` `m(S)=(12!)/(4!4!4!3!)3!=(12!)/(4!4!4!)` `n(E)=` the number of ways in which any one boy gets both the pens `="^(3)C_(1)^(10)C_(2)(8!)/(4!4!2!)2!=3xx45(8!)/(4!4!)` `:.P(E)=(3xx45(8!)/(4!4!))/((12!)/(4!4!4!))=(2)/(11)` `:.` Required probability `=1-(2)/(11)=(9)/(11)` |
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