1.

10) If one of the zero of p(x)=X2+a is -5 then find other zero.​

Answer»

<P>Answer:

5

Step-by-step explanation:

p(X) = x^2 + a

p(-5)= 0

p(-5) = 25+a = 0

a = -25

p(x) = x^2 -25

as a^2 - b^2 is (a+b)(a-b)

p(x) = (x+5)(x-5)

to FIND the VALUES

p(x) = 0

x = -5,5

so another zero is 5


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