1.

10 mg of an adsorbate gets adsorbed on a surface. This cause the release of 3J of heat constant pressure and at 27^(@)C. ["Molar mass of adsorbate" =100 g//mol]. (i) Find DeltaH_(AD) (ii) Argue whether the adsorption is physical or chemical? (iii) If 20 mg of adsorbate is adsorbed a temperature T_(0). Then compare T_(0) and 27^(@)C.

Answer»


Solution :mol`=10/100xx10^(-3)=10^(-4), DeltaH_(ADS)=3/10^(-4)=30 kJ`.
Adsorption is physical. Hence, the AMOUNT of substance adsorb will temperature. Therefore, `T_(0) lt 27^(@)C`.


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