10 ml mixture of H_(2), CH_(4) and CO_(2) was exploded with 15 ml of oxygen. After treatment with KOH the vloume reduced by 6 ml and again on treatment with alkaline pyrogallol, the volume further reduced by 3 ml. Then volume of H_(2) in mixture.

10 ml mixture of H_(2), CH_(4) and CO_(2) was exploded with 15 ml of o

1.	10 ml mixture of H_(2), CH_(4) and CO_(2) was exploded with 15 ml of oxygen. After treatment with KOH the vloume reduced by 6 ml and again on treatment with alkaline pyrogallol, the volume further reduced by 3 ml. Then volume of H_(2) in mixture.
Answer» 6 ML 1 ml 5 ml 4 ml Solution :`{:(H_(2) (g),+,(1)/(2)O_(2) (g),rarr,H_(2)O(l),),(x,,(x)/(2),,,),(-,-,-,,,):}` `{:(CH_(2) (g),+,2O_(2) (g),rarr,CH_(4) (g),+,2H_(2)O(g),),(y,,2y,,-,,-,),(-,,-,,y,,-,):}` `CO_(2) (g) + O_(2) (g) rarr x` `10 - (x + y)` `V_(CO_(2))` (total) = 6 mL (absorbed by KOH) `y + 10 - (x - y) = 6` `10 - x = 6` `x = 4 mL` `V_(H_(2)) = 4 mL` `V_(O_(2)) = 15 - ((x)/(2) + 2y) = 3` (absorbed by alkaline PYROGALLOL) `V_(O_(2)) = 12 = (x)/(2) + 2y` `x + 4y = 24` `4y = 20` `y = 5` `V_(O_(2)) = 5 mL`