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10 mL of 0.1 M-HCI solution is added in 90 mL of a buffer solution having 0.1 M-NH_(4)OH and 0.1 M-NH_(4)CI. The percentage change in pH of solution is (K_(a) " of " NH_(4)^(+) = 5xx10^(-10))[log 2 = 0.3] : |
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Answer» `(10)/(4.7) %` INCREASE |
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