1.

10 Ml of 1M of H_(2)SO_(4) will completely neutralise

Answer»

10 ML of 1M NAOH solution
10 ml of 2M NaOH solution
5 ml of 2 M KOH solution
5 ml of 1 M `Na_(2)CO_(3)` solution

Solution :`H_(2)SO_(4) + 2H_(2)O hArr 2H_(3)O^(+) + SO_(4)^(--)`
`NaOH hArr Na^(+) + OH^(-)`
1 MOLE of `H_(2)SO_(4)` acid gives 2 MOLES of `H_(3)O^(+)` ions. So 2 moles of `OH^(-)` are required for complete neutralization.


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