1.

10 mL of a gaseous hydrocarbon require 30 mL of oxygen for complete combustion. The hydrocarbon is

Answer»

`C_2 H_4`
`C_2 H_2`
`C_2 H_6`
`C_3 H_6`

Solution :(i) `underset(10 mL) (C_(2) H_(4)) + underset(30 mL) (3O_2) to underset(-) (2 CO_2) + underset(-) (H_(2)O)`
(II) `underset(10 mL) (C_2 H_2) + underset(25 mL) (5//2 O_2) to underset(-) (2 CO_2) + underset(-) (H_(2)O)`
(iii) `underset(10mL) (C_2 H_6)+ underset(35 mL) (7//2 O_2) to 2 CO_2 + 3H_2O`
(iv) `underset(10 mL) (C_3 H_6) + underset(45 mL) (9//2 O_2) to 3 CO_2 + 3 H_2O`
It is evident from EQ. (i) that 10 mL of `C_2 H_4` will require 30 mL of `O_2` ,therefore , hydrocarbon is `C_2 H_4`.


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