1.

10 ml of concentrated HCl were diluted to 1 litre. 20 ml of this diluted solution required 25 ml of 0.1 N sodium hydroxide solution for complete neutralization, the normality of the concentrated acid will be

Answer»

8
9.5
12.5
15

Solution :`{:(HCl,NaOH),(N_(1)V_(1)=,N_(2)V_(2)):}`
`N_(1)xx20ml=0.1xx25impliesN_(1)=(0.1xx25)/(20)=0.125`
If one LITRE HCl present in 0.125
Therefore in 10 ml `=(0.125)/(1000)xx100=12.5`
The normality of CONC. `HCl` is 12.5 N.


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