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10 mL of mixture containing carbon monoxide and nitrogen required 7mL, oxygen to form CO_(2) and NO, on combustion The volume of N_(2) in the mixture will be: |
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Answer» 7/2mL `N_(2)(g)+O_(2)(g)rarr2NO(g)` `X+y=10` `(x)/(2)+y=7` Solving eqs, i and II, `x=6` and y=4 |
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