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10 mole of CH3COOH of Ka=10−3 is dissolved in 10−3m3 water, 100 mL of resulting solution is mixed with 100 mL of NaOH of 10−3 M. If the products obtained in this neutralisation reaction are electrolysed then moles of gases which are produced at anode is x×10−2. The value of x is

Answer» 10 mole of CH3COOH of Ka=103 is dissolved in 103m3 water, 100 mL of resulting solution is mixed with 100 mL of NaOH of 103 M. If the products obtained in this neutralisation reaction are electrolysed then moles of gases which are produced at anode is x×102. The value of x is


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