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`10 "mole of" kSO_(2)` and `15 "mole of" O_(2)` were passed over catalyst to produce `8 "mole of" SO_(3)`. The ratio of `SO_(2)` and `SO_(3)` moles in mixture is:A. `5//4`B. `1//4`C. `1//2`D. `3//4` |
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Answer» Correct Answer - B `{:(,SO_(2)+,1//2O_(2)hArr,SO_(3),),("Initial mole",10,15,,),("Final mole",10-x,15-x/2,x,):}` `x=8` `:. SO_(2):SO_(3)::2:8` |
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