1.

10 resistors 1 ohm each are joined in series and then in parallel. what will be the ratio of effective resistance of the first to that of the second?​

Answer»

ANSWER:

Step-by-step explanation:

Answer:

When they are JOINED in series, the EFFECTIVE resistance is just their sum. Eff. Resistance(R) = 1 + 1 + upto 10 TERMS= 10

When they are joined in parallel, let the effective resistance be R, so: 1/R₁ = 10 →

R₁ = 1/10

1/R₁ = 1/1 + 1/1 + upto 10 terms

Hence, ratio of eff. resistance of 1st to that

of 2ND is:

R/R₁

(10)/(1/10)

⇒ 100: 1



Discussion

No Comment Found

Related InterviewSolutions