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10 resistors 1 ohm each are joined in series and then in parallel. what will be the ratio of effective resistance of the first to that of the second? |
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Answer» Step-by-step explanation: Answer: When they are JOINED in series, the EFFECTIVE resistance is just their sum. Eff. Resistance(R) = 1 + 1 + upto 10 TERMS= 10 When they are joined in parallel, let the effective resistance be R, so: 1/R₁ = 10 → R₁ = 1/10 1/R₁ = 1/1 + 1/1 + upto 10 terms Hence, ratio of eff. resistance of 1st to that of 2ND is: R/R₁ (10)/(1/10) ⇒ 100: 1 |
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