10 years before, the ages of a mother and her daughter were in the ratio 3: 1. On another 10 years from now, the ratio of their ages will be 13: 7. What are their present ages?

10 years before, the ages of a mother and her daughter were in the rat

1.	10 years before, the ages of a mother and her daughter were in the ratio 3: 1. On another 10 years from now, the ratio of their ages will be 13: 7. What are their present ages?
Answer» ) 27 yrDescription for Correct answer:Let the ages of A and B 10 yr before were 13x yr and 17X yr, respectively.Then, present age of A = 13x + 10 and present age of B = 17x + 10According to the question,\( \large\frac{13x + 10 + 17}{17x + 10 + 17} = \frac{10}{11} \)\( \large\frac{13x + 27 }{17x + 27} = \frac{10}{11} \)Hence, present age of B = 17 x 1 + 10 = 27yrPart of SOLVED Problem on ages questions and ANSWERS : >> Aptitude >> Problem on agesStep-by-step explanation:hope it will HELP you please follow me and mark me as brainlist

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10 years before, the ages of a mother and her daughter were in the ratio 3: 1. On another 10 years from now, the ratio of their ages will be 13: 7. What are their present ages?​

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10 years before, the ages of a mother and her daughter were in the ratio 3: 1. On another 10 years from now, the ratio of their ages will be 13: 7. What are their present ages?