1.

100" cm"^(3)" of "1" M "CH_(3)COOH was mixed with 100" cm"^(3)" of "2" M "CH_(3)OH to form an ester. The change in the initial rate if each solution is diluted with equal volume of water would be

Answer»

4 times
0.25 times
2 times
0.5 times

Solution :`underset(1M)(CH_(3)COOH)+underset(2M)(CH_(3)OH)toCH_(3)COOCH_(3)+H_(2)O`
Rate `(r_(1)) = K[CH_(3)COOH][CH_(3)COH]`
`= k(1)(2) = 2K`
When each solution is DILUTED with equal volume of WATER, concentration of each is halved, Now, rate
`r_(2) = k((1)/(2))((2)/(2)) =(k)/(2) therefore (r_(2))/(r_(1)) = (k//2)/(2k) = (1)/(4) = 0.25`
or `r_(2) =0.25 r_(1)`


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