100 g of a sample of HClsolution of relative density 1.17 contains 33.4 g of HCl . What volume of this HCl solution will be required to neutralise exactly5 litres of N/10NaOH solution ?

100 g of a sample of HClsolution of relative density 1.17 contains 33.

1.	100 g of a sample of HClsolution of relative density 1.17 contains 33.4 g of HCl . What volume of this HCl solution will be required to neutralise exactly5 litres of N/10NaOH solution ?
Answer» SOLUTION :Volume of HCl solution ` = 100/(1.17) mL ` `(" density " = ("mass")/("volume"))` Equivalents of HCl = `(33.4)/(36.5)` (eq.wt . Of HCl = 36.5) m.e of HCl ` = (33.4)/(36.5) xx 1000 "" … (Eqn . 3)` NORMALITY of HCl = `("m.e")/(" volume in mL") "" ....(Eqn .1)` ` =(33.4)/(36.5) xx 1000 xx (1.17)/100` ` = 10.7 ` N Now let the volumeof HCl, of normality calculated above , REQUIRED to neutralise exactly the given NaOH solution be v mL . Now let the volume of HCl , of normality calculated above , required to neutralise exactly the given ,naOH solution be v mL . m.e of HCl = m.e of NaOH `10.7 xx v = 1/10 xx 5000` ` 10 . 7xx v 1/10 xx 5000` `10.7 xx v = 500` ` :. "" v = 46.7 mL `