1.

100 gms of 118% oleum reacted with excess water. How much H_(2)SO_(4) is formed?

Answer»

90 gm
118 gm
48 gm
100 gm

SOLUTION :`SO_(3)+H_(2)SO_(4) to H_(2)S_(2)O_(7), H_(2)S_(2)O_(7)+H_(2)O to 2H_(2)SO_(4)`
`SO_(3)` is absorbed in `98%` conc. `H_(2)SO_(4)` to get oleum. Oleum `[H_(2)S_(2)O_(7)]` is diluted with water to get `H_(2)SO_(4)`
118% of oleum `to` 100 gm
`"?" larr 100%`, 118grams.


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