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100 gram of ice at `0^@C` is converted into water vapour at `100^@C` Calculate the change in entropy. |
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Answer» `underset(0^(@)C)"ice"rarrunderset(0^(@)C)"Water"` `DeltaS_1=(DeltaQ)/(T_1)=(mL_(ice))/(T_1)=(100xx80)/(273)=29.3(cal)/(K)` `underset(0^(@)C)"Water"rarrunderset(100^(@)C)"Water"` `DeltaS_2=ms_(omega)ln(T_2)/(T_1)=100xx1xxln((373)/(273))` `=100ln(1.4)(cal)/(K)` `underset(100^(@)C)"Water"rarrunderset(100^(@)C)"Vapour"` `DeltaS=(DeltaQ)/(T_2)=(mL_(stream))/(T_2)=(100xx540)/(373)=144.8(cal)/(K)` Not change in entropy `DeltaS=DeltaS_1+DeltaS_2+DeltaS_3` `=29.3+100ln(1.4)+144.8` `=174.1+100ln(1.4)(cal)/(K)` |
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