1.

100 mg of a protein is dissolved in just enough water to make 10.0 mL of solution. If this solution has an osmotic pressure of 13.3 mm Hg at 25^(@)C, what is the molar mass of protein?

Answer»


Solution :`M_(2)=(WRT)/(PIV)=((8.95xx10^(-3)g)(0.0821"L ATM K"^(-1)"mol"^(-1))(298K))/(("0.335/760 atm")(35xx10^(-3)L))="14193.3 g mol"^(-1)`


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