1.

100 ml 0.2 M Na_(2)Ais titrated with 100ml 0.03 M HCl. Calculate pH of final solution. pKa_(1)(H_(2)A)=5""pKa_(2)(H_(2)A)=9

Answer»

2
7.5
5
9

Solution :`SO_(2)Cl_(2)(g)rarrSO_(2)(g)+Cl_(2)(g)`
0.5
`0.5-x ""x""x`
`K_(A)=(1)/(100)LN.(0.5)/(0.25)=(ln2)/(100)`
Rate `=KP_(A) = (ln2)/(100)xx0.3=2.1xx10^(-3)"atm"//"sec"`


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