1.

100 ml Fe(OH)_​(3) is coagulated by 10 ml 1N Na_​(2)​SO​_(4)​. Then what will becoagulation value of Na_(​2)​SO​_(4)​?

Answer»

5
10
50
100

Solution :100 ML `FE(OH)_3 ` is coagulated by =`10xx1/2`=5 milli MOL
1 mol `Fe(OH)_3` is coagulated by = `5/100`
1000 ml `Fe(OH)_3` is coagulated by`=(1000xx5)/100`=50


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