1.

100 ml of 0.04 N HCl aqueous solution is mixed with 100 ml of 0.02 N NaOH solution. The pH of the resulting solution is

Answer»

`1.0`
1.7
`2.0`
2.3

Solution :`N_(1)V_(1) = 0.04 XX 100 = 4`
`N_(2)V_(2) = 0.02 xx 100 =2`
`N_(1)V_(1) - N_(2)V_(2) = N_(3)V_(3)`
`4-2 = N_(3) xx 200, N_(3) = 10^(-2) M`
`pH = LOG 10 (1)/(10^(-2)) = 2`.


Discussion

No Comment Found

Related InterviewSolutions