1.

100 ml of 0.2 M H_(2)SO_(4) is added to 100 ml of 0.2 M NaOH. The resulting solution will be

Answer»

Acidic
Basic
Neutral
Slightly basic

Solution :M.eq. of 0.2 M `H_(2)SO_(4) = (2 xx 0.2 M)/(1000) xx 100 = 0.04 m//l`
M.eq. of 2M NaOH `= (0.2)/(1000) xx 100 = 0.02 m//l`
LEFT `[H^(+)] = .04 - .02 = .02`
Total volume `= 200 = (.02)/(200) =.0001 = 10^(-4)M`
pH =4.


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